Thermodynamics · Anno 1824

The Carnot Cycle

The theoretically perfect heat engine — four steps between two heat reservoirs, formulated by the 28-year-old Sadi Carnot eight years before his death. No real engine can beat its efficiency.

In 1824 the young French engineer Sadi Carnot published a small treatise entitled Réflexions sur la puissance motrice du feu — Reflections on the Motive Power of Fire. The question was practical: what is the maximum work you can get out of a steam engine? The answer became one of the deepest insights of thermodynamics: the efficiency depends only on the temperatures of the hot and the cold reservoir — not on the working fluid, not on the design of the engine.

The cycle consists of four reversible processes: two isothermal (at constant temperature) and two adiabatic (with no heat exchange). Press play below and follow the gas round the loop.

W Th · hot reservoir Tc · cold reservoir insulated · no Q Qh → ← Qc ↓
Cylinder with piston · working fluid: ideal gas (1 mol He)
P-V diagram · red = isotherm at Th · blue = isotherm at Tc · purple = adiabats
01 Isothermal expansion T = Th · gas takes in Qh
02 Adiabatic expansion Q = 0 · T falls Th → Tc
03 Isothermal compression T = Tc · gas gives out Qc
04 Adiabatic compression Q = 0 · T rises Tc → Th
Speed:
Pressure— kPa
Volume— L
Temperature— K
Qh taken in0 J
Qc given out0 J
Work W0 J
Efficiency η— %

Adjust the cycle's parameters

600 K
300 K
2.0 ×

Slide Th higher or Tc lower — you will see the efficiency rise. That is the essence of the second law of thermodynamics.

The four processes — formulae

For an ideal gas with n moles, gas constant R and adiabatic index γ:

① Isothermal expansion at Th

Qh = nRTh · ln(V₂/V₁) ΔU = 0 ⇒ W₁ = Qh

The gas is in contact with the hot reservoir. It expands slowly, takes in heat Qh and does an equal amount of work.

② Adiabatic expansion

T·Vγ−1 = constant W₂ = nCv · (Th − Tc)

The cylinder is insulated. The gas expands further, but now at the expense of its own internal energy — the temperature falls from Th to Tc.

③ Isothermal compression at Tc

Qc = nRTc · ln(V₃/V₄) ΔU = 0 ⇒ W₃ = −Qc

The gas is in contact with the cold reservoir. It is compressed, gives out heat Qc, and work is done on the gas.

④ Adiabatic compression

T·Vγ−1 = constant W₄ = −nCv · (Th − Tc)

Insulated again. The continued compression raises the gas temperature from Tc back to Th. The cycle is closed.

The beautiful result

The adiabats ensure that V₂/V₁ = V₃/V₄. So the net work is:

Wnet = Qh − Qc = nR(Th − Tc) · ln(V₂/V₁) η = W/Qh = 1 − Tc/Th

The efficiency depends solely on the two temperatures — not on the gas, not on the volumes.

Carnot's theorem (1824): No heat engine operating between two reservoirs at Th and Tc, can have a higher efficiency than the reversible Carnot engine. All reversible engines between the same two reservoirs have the same efficiency. William Thomson (Lord Kelvin) used this theorem to define the absolute temperature scale.

Worked example

A steam power station · Th = 773 K (500 °C), Tc = 298 K (25 °C)

A modern coal-fired power station has a boiler at 500 °C and a condenser at 25 °C (ambient temperature). What is the theoretical maximum efficiency?

Step 1. Convert to kelvin:
Th = 500 + 273 = 773 K · Tc = 25 + 273 = 298 K
Step 2. Use the Carnot efficiency:
ηCarnot = 1 − Tc/Th = 1 − 298/773 = 1 − 0.3855 = 0.614 = 61.4 %
Step 3. Real power stations reach typically 35–45% — everything between that and the Carnot limit is lost to irreversibilities: friction, heat conduction across a finite temperature difference, turbulence, incomplete combustion.

Question: How much work do we get per kg of coal burned (heat of combustion ≈ 30 MJ/kg)?

At the Carnot limit: W = 0.614 × 30 MJ = 18.4 MJ per kg of coal
In a real power station (η = 40%): W = 0.40 × 30 MJ = 12 MJ per kg of coal

Mole-by-mole calculation · 1 mol helium, Th = 600 K, Tc = 300 K, V₂/V₁ = 2

Qh (heat taken in):
Qh = nRTh · ln(V₂/V₁) = 1 · 8.314 · 600 · ln(2) = 1 · 8.314 · 600 · 0.6931 = 3457 J
For helium (γ = 5/3), V₃ is found:
V₃ = V₂ · (Th/Tc)1/(γ−1) = V₂ · 23/2 = 2.828 · V₂
Similarly V₄ = 2.828 · V₁. Note V₃/V₄ = V₂/V₁ = 2 — the two adiabats cut the two isotherms in the same volume ratio.
Qc (heat given out):
Qc = nRTc · ln(V₃/V₄) = 1 · 8.314 · 300 · ln(2) = 1729 J
Work and efficiency:
Wnet = Qh − Qc = 3457 − 1729 = 1728 J
η = W/Qh = 1728/3457 = 0.500 = 50.0 %
Check: 1 − Tc/Th = 1 − 300/600 = 0.500 ✓

Comparison with real engines

The Carnot efficiency is the ceiling no real engine can reach. Here is a selection of engines, their typical operating temperatures and how close they come:

Engine Th Tc ηCarnot η (real)
Steam locomotive (classic) 473 K (200 °C) 373 K (100 °C) 21.1 % ~6–10 %
Car engine (petrol) 2300 K 400 K 82.6 % ~30 %
Diesel engine (ship) 2100 K 500 K 76.2 % ~50 %
Coal-fired power station 773 K (500 °C) 298 K (25 °C) 61.4 % ~40 %
Combined-cycle gas power station 1700 K 300 K 82.4 % ~60 %
Geothermal power station 473 K (200 °C) 290 K (17 °C) 38.7 % ~12 %

Notice the interesting point: the car engine has the highest Carnot ceiling (over 80%) but reaches only about 30%. It is limited not mainly by thermodynamics but by irreversibilities — fast combustion, friction, heat loss through the cylinder, incomplete exhaust. The coal-fired power station, by contrast, comes considerably closer to its own Carnot ceiling: it is a large, steady-state plant in which heat is recovered at several stages (feed-water heating, reheating) and losses can be kept small.

Refrigerator and heat pump — Carnot in reverse

If the Carnot cycle is run backwards (anticlockwise in the P-V diagram), it becomes a refrigerator: work is put in, and heat is pumped from the cold to the hot reservoir. The measure of performance is not η but the COP (coefficient of performance):

COPcooling = Tc / (Th − Tc) COPheat pump = Th / (Th − Tc)

A heat pump that lifts heat from 0 °C outdoors (273 K) to 35 °C in underfloor heating (308 K) has a Carnot COP = 308/35 ≈ 8.8 — that is, 8.8 kWh of heat delivered per kWh of electricity. Real heat pumps reach 3–5. That is still a factor of 3–5 better than direct electric heating, and explains why heat pumps are thermodynamics' best friend in the green transition.

What Carnot taught us

Carnot died of cholera in 1832, only 36 years old. His treatise attracted little attention in his own time, but when Rudolf Clausius and William Thomson took it up in the late 1840s and 1850s, it became the cornerstone of the whole of thermodynamics. Three deep consequences:

The Carnot cycle is the North Starof thermodynamics. It does not exist in nature — no process is completely reversible — but it tells us precisely how good an engine could be if it were perfect. The difference between ηCarnot and ηreal is the measure of irreversibility.

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